Question

2. The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

Answer 1

For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s