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A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y=-0.06x^2+9.6x+5.4 where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above ground.

How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth.

a.) 13.94 m
b.) 160.56 m
c.) 4.30 m
d.) 160.23 m

1 Answer

5 votes
For this case we have the following equation:
y = -0.06x ^ 2 + 9.6x + 5.4
What we should do for this case is:
Match the equation to zero:
-0.06x ^ 2 + 9.6x + 5.4 = 0
Find the roots of the polynomial, which are given by:
x1 = -0.56
x2 = 160.56
Since we are talking about a distance, then we discard the negative root.
Answer:
b.) 160.56 m
User JRowan
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