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The magnitude of the weight of a 3.0 kg object on the surface of the earth is 29 N. True False

2 Answers

7 votes

Answer:

True

Step-by-step explanation:

3.0 * 9.8 = 29 N

User Cyva
by
5.6k points
2 votes
True

In fact, the weight of an object on the surface of the Earth is given by:

F=mg
where m is the mass of the object and
g=9.81 m/s^2 is the gravitational acceleration on Earth's surface. If we use the mass of the object, m=3.0 kg, we find

F=mg=(3.0 kg)(9.81 m/s^2)=29 N
User Jiri Volejnik
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6.3k points