Question

Find the length of a simple pendulum that has a period of 1.00 s. Assume that the acceleration of gravity is g

Answer 1

The length of the simple pendulum is 0.248 m.

Step-by-step explanation:

Given;

period of the simple pendulum, T = 1.00 s

let the length of the simple pendulum = L

The period of oscillation of a simple pendulum is calculated as;

`T = 2\pi \sqrt{(l)/(g) } \\\\(T)/(2\pi ) = \sqrt{(l)/(g) }\\\\(T^2)/(4\pi ^2 ) = (l)/(g)\\\\l = (gT^2)/(4\pi ^2 ) \\\\l = ((9.8)(1)^2)/(4\pi ^2 ) \\\\l = 0.248 \ m`

Therefore, the length of the simple pendulum is 0.248 m.