Question

1. A student was taking a rock-climbing class that used an indoor climbing wall. Before he started, the instructor asked for his weight. If the student had a mass of 88.6 kg, what was his weight? (2 points) Weight is the downward force of gravity, measured in Newtons, which is: F = m*g = 88.6kg * 9.81 m/s^2 = 869 N (3 s.f.) The equation above is Newton's 2nd Law of Motion where g is the acceleration due to gravity near the Earth's surface. 2. The student stood at the bottom of the wall and then started to climb the wall. Explain how :a. Newton's third law relates to the wall b. Newton's first law relates to the student (4 points: 2 points each part) the student exerts a force called action which is equal to its weight on the wall and the wall exerts an equal force called reaction onto the student standing in the opposite direction. 3. The same student was moving up the wall with an acceleration of 0.0003 m/s2. What was the force his muscles were using? (Hint: You will need the value of mass from question 1.) (2 points) ONLY ANSWER QUESTION 3 PLEASE... QUESTION 1 AND 2 ARE ALREADY ANSWERD

Answer 1

According to the second law of motion, also known as the law of acceleration, force is the product of mass and acceleration:
F=ma
Where:
m=mass
a=acceleration

The given in the problem are:
m = 88.6kg
a= 0.0003m/s^2

You can compute the force using the formula:
F=ma
F=(88.6kg)(0.0003m/s^2)
F=0.03kg.m/s^2 or 0.03N

The force is 0.03N.