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What is the axis of symmetry of h(x)=5x^+40x+64

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\text{The axis of symmetry of}\ f(x)=ax^2+bx+c\ is\ x=(-b)/(2a).\\\\\text{We have:}\ h(x)=5x^2+40x+64\\\\\text{substitute:}\ x=(-40)/(2\cdot5)=(-40)/(10)=-4.\\\\Answer:\ \boxed{x=-4}
What is the axis of symmetry of h(x)=5x^+40x+64-example-1
User Jordan H
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