Question

If 2.00 mol of gas occupies 4.50l at stp. how much of the same gas will occupy a container that is 1/2 the size?

Answer 1

Avagadros law states that the volume of a gas is directly proportional to the number of moles at constant temperature and pressure conditions

`(V)/(n)` = k
where V - volume
n - number of moles and k - constant

`(V1)/(n1) = (V2)/(n2)`
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
V1 - 4.50 L
V2 - 1/2 x 4.50 = 2.25 L
n1 - 2.00 mol
substituting the values in the equation

`(4.50L)/(2.00 mol) = (2.25 L)/(n)`
n = 1.00 mol
1.00 mol of the gas is present when container is 1/2 in size