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In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?

In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?
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In a second trial of this experiment, the molarity of koh(aq) was determined to be 0.95 m. the actual molarity was 0.83 m. what is the percent error in the second trial?

User Yakau Bubnou
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1 Answer

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The % error in the second trial is calculated as follows

% error = actual molarity/ theoretical molarity x100


= 0.83/0.95 x100 = 87.4% error of second trial
User Otabek Kholikov
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