Question

A woman who is colorblind marries a man with normal vision. what are the chances that their daughters will be carriers for colorblindness?

Answer 1

`(1)/(4)`
because there mother is colorblind c is carrier gene and b is colorblindness gene

`x^(c) {x}^(b)`
and their dad isn't so

`{xy}`
chances:

`{x}^(c) {x}`
normal vision daughter and a carrier

`{xx}^(b)`
colorblind daughter

`{x}^(c)y`
normal vision son and a carrier

`{x}^(b) y`
colorblind son