Question

Choose the correct answer. two cars leave phoenix and travel along roads 90 degrees apart. if car 1 leaves 30 minutes earlier than car 2 and averages 42 mph and if car 2 averages 50 mph, how far apart will they be after car 1 has traveled 3.5 hours? miles.

Answer 1

The answer is 210 miles.

Answer 2

The equation of movement for each car is given by:
Car 1:
d1 = v1 * t1
Substituting values:
d1 = 42 * 3.5
d1 = 147 miles
Car 2:
d2 = v2 * t2
d2 = v2 * (t1 + 0.5)
Substituting values:
d2 = 50 * (3.5 + 0.5)
d2 = 200 miles
The distance between the cars is:
d = root ((d1) ^ 2 + (d2) ^ 2)
d = root ((147) ^ 2 + (200) ^ 2)
d = 248.2 miles
Answer:
They will be 248.2 miles far.