Question

A rope 6m long is fixed at one end; the other end is attached to a light string so that it is free to move. The speed of waves on the rope is 18 m/s. The frequency of the second harmonic is

Answer 1

Given :

A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.

The speed of waves on the rope is 18 m/s.

To Find :

The frequency of the second harmonic.

Solution :

We know, for second harmonic wave :

Wavelength = Length of rope

`\lambda = L\\\\\lambda = 6 \ m`

Now, we know frequency is given by :

`Frequency = (Speed)/(Wavelenght)\\\\f = (18 \ m/s)/(6\ m)\\\\f = 3 \ s^(-1)`

Therefore, the frequency of the second harmonic is 3 s⁻¹.