Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

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asked Jan 16, 2019 221k views

2 Answers

HemOdd · Answer 1 · 2019-01-21T10:48:57+0000

x=-2 and y=5

(3x^3y^-2)^2=[3(-2)^3 (5)^(-2)]^2=[3(-8)/(5)^2]^2=(-24/25)^2=(-24)^2/(25)^2

(3x^3y^-2)^2=576/625

Answer: The value of the expression is 576/625

Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

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