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Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2
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Which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

User Nishita
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2 Answers

2 votes

Answer:

Option 1 - 32(-2)6/54

User Brandon Deo
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x=-2 and y=5

(3x^3y^-2)^2=[3(-2)^3 (5)^(-2)]^2=[3(-8)/(5)^2]^2=(-24/25)^2=(-24)^2/(25)^2

(3x^3y^-2)^2=576/625

Answer: The value of the expression is 576/625
User HemOdd
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