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Gizzmo · Answer 1 · 2019-01-28T22:32:58+0000

$m\angle BAE=180^o-(360^o)/(5)=180^o-72^o=108^o$

We know, in a triangle, the three interior angles always add to 180° and in
an isosceles triangle are two equal angles.

Therefore in ΔEBA

$m\angle AEB=(180^o-108^o)/(2)=(72^o)/(2)=36^o.$

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