Question

A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of 0.060 m>s. After 1.5 minutes the finch tires of

Answer 1

Complete Question:

A finch rides on the back of a Galapagos tortoise, which walks

at the stately pace of 0.060 m/s. After 1.5 minutes the finch tires of

the tortoise’s slow pace, and takes flight in the same direction for

another 1.5 minutes at 11 m/s.

What was the average speed of the finch for this 3.0-minute interval?

Answer:

`Speed = 5.53 m/s`

Step-by-step explanation:

Distance is calculated as:

`Distance = Speed * Time`

First, we calculate the distance for the first 1.5 minutes

For the first 1.5 minutes, we have:

`Speed = 0.060m/s`

`Time = 1.5\ mins`

`D_2= 0.060m/s * 1.5\ mins`

Convert 1.5 mins to seconds

`D_2= 0.060m/s * 1.5 * 60s`

`D_2= 5.4m`

Next, we calculate the distance for the next 1.5 minutes

`Speed = 11m/s`

`Time = 1.5\ mins`

`D_2= 11m/s * 1.5\ mins`

Convert 1.5 mins to seconds

`D_2 = 11m/s * 1.5 * 60s`

`D_2= 990m`

Total distance is:

`Distance = 990m + 5.4m`

`Distance = 995.4m`

The average speed for the 3.0 minute interval is:

`Speed = (Distance)/(Time)`

`Speed = (995.4\ m)/(3.0\ mins)`

Convert 3.0 minutes to seconds

`Speed = (995.4\ m)/(3.0 * 60 secs)`

`Speed = (995.4\ m)/(180 secs)`

`Speed = 5.53 m/s`