Answer:
The correct option is option a.
Explanation:
It is given that parallelogram DEFG is transformed to parallelogram VSTU.
It means we have a parallelogram DEFG and after transformation we get VSTU.
Since the original figure is DEFG, therefore DEFG is preimage and VSTU is the image because it is the result of the transformation.
Therefore option a is correct, i.e., "Parallelogram DEFG is the pre-image because it is not the result of the transformation".