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The length of a rectangle is 3 inches more than it's worth, and it's perimeter is 22 inches. What the width

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W = width of the rectangle

L = length, W + 3


\bf \textit{perimeter of a rectangle}\\\\ P=2(L+W)~~ \begin{cases} L=length\\ W=width\\ ------\\ P=22\\ L=W+3 \end{cases}\implies 22=2[(W+3)+W] \\\\\\ \cfrac{22}{2}=2W+3\implies 11=2W+3\implies 8=2W \\\\\\ \cfrac{8}{2}=W\implies 4=W
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