The reaction between methane (CH4) and bromine (Br2) substitutes one hydrogen atom in methane with a bromine atom, forming bromomethane (CH3Br) and hydrogen bromide (HBr). A Br-Br bond is broken, and a new C-Br bond is created.
The reaction between methane (CH4) and bromine (Br2) typically involves a substitution where one hydrogen atom in the methane is replaced by a bromine atom. The structural diagram for this reaction is as follows:
CH4 + Br2 → CH3Br + HBr
The methane molecule starts with four hydrogen atoms bonded to a central carbon atom, creating a tetrahedral structure. When one of these hydrogen atoms is replaced by a bromine atom, the product is bromomethane (CH3Br), also known as methyl bromide, and hydrogen bromide (HBr).
The structural formula for bromomethane shows the central carbon atom connected to three hydrogen atoms and one bromine atom. During the reaction, a Br-Br bond is broken and a new C-Br bond is formed.