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Solve the system below. y = x^2 - 4 y= -4 a. 0 , -4 b. -4, 0 c. (0, -4), (-4, 0) d. there is no real solution
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Solve the system below.

y = x^2 - 4

y= -4

a. 0 , -4
b. -4, 0
c. (0, -4), (-4, 0)
d. there is no real solution

User Jzheaux
by
5.2k points

1 Answer

5 votes
To solve this system, let y = x^2 - 4 = -4.  Then y = x^2.  This is true for all x.  There is no single numerical solution.  y = x^2 is a function with infinitely many inputs/outputs.
User Skitzafreak
by
5.3k points
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