Question

What is the force on an electron in a CRT when it’s moving at 2.5 × 105 meters/second perpendicular to a magnetic field of 1.5 teslas? The charge for an electron is -1.6 × 10-19 coulombs.

Answer 1

F = Magnetic Force
B = Magnetic Field
V = Velocity

*The vectors from the photo you get doing the left-hand rule.

The magnetic force is always perpendicular to the magnetic field.

And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.

The formula to find the Magnetic Force is:


`f = |q| * v * b * sin \: \theta`

Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.


`f = |- 1.6 * {10}^( - 19) | * 2.5 * {10}^(5) * 1.5 * 1 \\ f = 6 * {10}^( - 19 + 5) \\ f = 6 * {10}^( - 14) \: newtons`
Newton (N) = C x m/s x T = (C x m x T)/s