Question

The two charges are then brought closer together so that the force between them increases by a factor of 25. By what factor was their separation decreased

Answer 1

Step-by-step explanation:

The forces between two charges is inversely proportional to the square of distance.

`F = k q_1 q_2 / r^(2)`

So if the distance is half then the force increases by a factor of 4 . if force between the charges increases by a factor of 25 then separation between them is decreased by a factor of 5 i.e distance between them is 1/5.