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Write the equation of a line with a slope of 5/2 and passes through the point (2,3)

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Answer:

y - 3 = ⁵/₂(x - 2) {the point-slope form of the equation}

y = ⁵/₂x - 2 {the slope-intercept form of the equation}

5x - 2y = 4 {the standard form of the equation}

Explanation:

The point-slope form of equation is: y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope.

m = ⁵/₂

(2, 3) ⇒ x₀ = 2, y₀ = 3

So, the point-slope form of the equation:

y - 3 = ⁵/₂(x - 2)

Therefore:

y - 3 = ⁵/₂x - 5 {add 3 to both sides}

y = ⁵/₂x - 2 ← the slope-intercept form of the equation

-⁵/₂x + y = - 2 {multiply both sides by (-2)}

5x - 2y = 4 ← the standard form of the equation

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