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Find the difference 7/x^2-3x - 1/x^2-9

User Jazline
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1 Answer

2 votes
To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

7/x^2-3x - 1/x^2-9

2. When you factor the denominator, you obtain:

7/x(x-3) - 1/(x+3)(x-3)


3. By simplifying the expression, you obtain:

3(2x+7)/x(x+3)(x-3)
3(2x+7)/x(x^2-9)

The answer is:
3(2x+7)/x(x^2-9)
User ZooKeeper
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