Answer:
Chiara has 2 penny coins and 24 nickel coins
Explanation:
Let
p ----> the number of penny coins
n ---> the number of nickel coins
Remember that


Chiara has 26 coins that equal 34 cents
so

isolate the variable x
----> equation A
34 cents=$0.34

Multiply by 100 both sides

isolate the variable x
-----> equation B
Create a table to guess
assume different values of n and determine the value of p in equation A and equation B
The solution is when the value of p in the equation A must be equal to the value of p in equation B
1) For n=1
equation A

equation B


2) For n=2
equation A

equation B

therefore
The solution is (2,24)
Chiara has 2 penny coins and 24 nickel coins