Question

Abel was wrapping a gift for an upcoming party. He began with 20 1/2 feet of paper. He used 5 5/12 feet on his first gift and 3 1/3 feet on his second gift. If Abel bought 2 additional rolls of paper that each contained 10 1/2 feet, how many papers does he now have left for wraping.

Answer 1

Hey there!


`20 (1)/(2) - 5 (5)/(12) - 3 (1)/(3) + 2 * 10 (1)/(2) \\ = (41)/(2) - (65)/(12) - (10)/(3) + 21 \\ = (246)/(12) - (65)/(12) - (40)/(12) + 21 \\ = (141)/(12) + 21 \\ = 32 (3)/(4)`

Answer : 32 3/4 feet or in decimal form, 32.75 feet.

Hope this helps. - M

Answer 2

`\text {At first = } 20(1)/(2) \text{ feet}`


`\text {Used } 5(5)/(12) \text{ on the first gift : }`

`20(1)/(2) - 5(5)/(12)`

`= 20(6)/(12) - 5(5)/(12)`

`= 15(1)/(12) \text{ feet}`


`\text {Used } 3(1)/(3) \text{ on the second gift : }`

`15(1)/(12) - 3(1)/(3)`

`= 14(13)/(12) - 3(4)/(12)`

`= 11(9)/(12)`

`= 11(3)/(4)\text{ feet}`


`\text {Bought additional 2 rolls of } 10(1)/(2) \text{ feet each : }`

`11(3)/(4) + 10(1)/(2) + 10(1)/(2)`

`= 11(3)/(4) + 10(2)/(4) + 10(2)/(4)`

`= 31(7)/(4)`

`= 32(3)/(4) \text{ feet}`


`\boxed{ \boxed{ \text{Answer: }32(3)/(4)\text{ feet}}}`