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If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

please help thank you.

User Geeky I
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1 Answer

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Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
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Find pH

pH = -log(1 * 10^-1)
pH = 1
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Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is
[OH-] = 1 * 10^(-13) mol/L

Hope this helps!
User Jaryl
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