Question

what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c

Answer 1

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

`Q = m * C * \bigtriangleup T`

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

`C = (Q)/(m * \bigtriangleup T)`

Let us plug in the values in above equation.

`C = (300J)/(267g * 12 C)`

`C = (300J)/(3204 g C)`

C = 0.0936 J/g °C

The specific heat of the substance is 0.0936 J/g°C