Question

A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds-How fast was the ball going when it left the boy's hand?

Answer 1

Answer is

`4g \: m {s}^( - 1)`

Step-by-step explanation:

We have to find the initial velocity, u.

Final velocity is v = 0. And acceleration is due to gravity.

Now,

`v = u + at`

`0 = u + ( - g)m {s}^( - 2) * 4s`

`u = 4g \: m {s}^( - 1)`

Therefore, the final answer depends on the value of g.