The correct answer is: 0.9 cal
Step-by-step explanation:
The formula for the specific heat (s) is:
s = (q)/(m * ΔT) --- (1)
Where
s = Specific heat = 0.09 cal/g°C
m = mass (make sure it is in GRAMS) = 10g
ΔT = Change in temperature = 21° - 20° = 1°
q = Heat Energy = ?
Plug in the values in the Equation (1):
(1) => q = (10*1*0.09) = 0.9 cal