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If you have 3.8 mol of k, how many atoms are present?

User Lee Dale
by
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2 Answers

4 votes

2.288 * 10^24

Use Avogardo’s Constant
User Daniel McQuiston
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5.4k points
5 votes

Answer : 2.29 x 10²⁴ atoms of K are present

Explanation :

Mole and number of particles are related to each other by Avogadro's constant.

According to this, 1 mole of any substance contains 6.022 x 10²³ number of representative particles. These representative particles could be atoms, molecules, ions or formula units.

So we can say that 1 mol of K will contain 6.022 x 10²³ atoms of K.

Let us use this as a conversion factor to set up an equation.

We have been given 3.8 mol K.


3.8 mol K*(6.022* 10^(23)atoms)/(1mol K)= 2.29 x 10²⁴ atoms of K

Therefore we have 2.29 x 10²⁴ atoms of K.


User Critical Skill
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5.3k points