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What is the volume occupied by 11.0 grams of a gas at STP if the molecular mass of the gas is 44.0?

1 Answer

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we can use the ideal gas law equation to find the volume occupied by the gas
PV = nRTwhere
P - standard pressure - 101 325 Pa
V - volume
n - number of moles - 11.0 g / 44 g/mol = 0.25 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - standard temperature - 273 K
substituting the values in the equation
101 325 Pa x V = 0.25 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K
V = 5.60 L
volume of the gas is 5.60 L
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