Question

Upon balancing the equation below, how many moles of calcium chloride are needed to react completely with 4.3 moles of silver nitrate? agno3 + cacl2 yields agcl + ca(no3)2 1.4 mol cacl2 2.2 mol cacl2 4.3 mol cacl2 8.6 mol cacl2

Answer 1

2.2 mol CaCl2 is the answer.

Answer 2

Answer: The correct answer is 2.2 moles of
`CaCl_2`

Step-by-step explanation:

For the given balanced equation:

`2AgNO_3+CaCl_2\rightarrow 2AgCl+Ca(NO_3)_2`

By Stoichiometry of the reaction:

2 moles of silver nitrate reacts with 1 mole of calcium chloride.

So, 4.3 moles of silver nitrate will react with =
`(1)/(2)* 4.3=2.15moles\approx 2.2moles` of calcium chloride.

Hence, the correct answer is 2.2 moles of
`CaCl_2`