let
x---------> longer leg
y--------> shorter leg
we know that
x=55+y
hypotenuse=2y-55
in a right triangle
c²=a²+b²
where
c is the hypotenuse
a and b are the legs
so
hypotenuse²=x²+y²------> (2y-55)²=(55+y)²+y²
4y²-220y+3025=y²+110y+3025+y²
2y²-330y=0------> divided by 2-----> y²-165y=0
using a graph tool
see the attached figure
the solution is
y=165 m
the answer is
the length of the shorter leg is 165 m