The correct answer is:
200kgStep-by-step explanation:
Let's apply the law of conservation of momentum:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ -- (1)
u₁ = Initial speed of mass one = -0.650c (negative sign indicates that this is moving towards the second mass)
u₂ = Initial speed of mass two = 0.85c
After collision the two are stick with each other, so according to (1) v₁ = v₂ = v (Final velocity):
The final velocity = v = (m₁u₁ + m₂u₂)/(m₁+m₂) = (-65+85)/(200) = 0.1c (after collision)
Now here is the trick! Most of the students would do the calculation like I did above and use the relativistic mass formula and put the velocity v which we computed above like:
m = m₀(sqrt (1 – v² / c² ))
BUT in the question the REST mass is required! In that case you do not need to apply the above formula; simply add both the mass after collision as they stick together; hence 100 + 100 = 200 kg (rest mass).