Question

Dave and sandy hartranft are frequent flyers with a particular airline. they often fly from city a to city​ b, a distance of 732732 miles. on one particular​ trip, they fly into the​ wind, and the flight takes 22 hours. the return​ trip, with the wind behind​ them, only takes 1 and one half1 1 2 hours. if the wind speed is the same on each​ trip, find the speed of the wind and find the speed of the plane in still air

Answer 1

Let the speed of the plane in still air = x
and speed of wind = y
Now from city A to B
dIstance = speed × time
732732 = (x - y) × 2 (1)
From city B to A
Distance = speed × time
732732 = (x + y) × 1.5 (2)
From (1) and (2)
2x - 2y = 1.5x + 1.5y
0.5x = 3.5y
x = 7y
If we plug in (1)
732732 = (7y - y) × 2
732732/12 = 12y/12
y = 61061
Since x = 7y
= 427427 miles/hr
Speed of still air plane is 427427 miles/hr
Speed of wind = 61061miles/hr