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If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
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If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
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Dec 2, 2019
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If the ph of hc3h5o2 is 4.2 and the ka 1.34x10^-5, what is the equilibrium concentration
Chemistry
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Sschmeck
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CH₃
CH
₂
COOH + H
₂
O
↔
CH
₃
CH
₂
COO
⁻
+ H
₃
O
⁺
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
= 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴
where Ca is the acid concentration
Jelly Ama
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Dec 8, 2019
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Jelly Ama
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