Question

find the area of a rectangle that has a length of 8.3 inches. and a width that is 0.6 times the length. show work please

Answer 1

Area=length×width
8.3
×0.6
=====
6×3=18 put down 8 and carry the
6×8=48 + the 1 =498
498...now count how many numbers are behind the decimals...2 = 4.98 4.98 × 8.3 = 41.334in (2)

Answer 2

find the width first...8.3×0.6.....then find the area....length × width= 8.3×4.9=40.67....that's what I got