Question

You work as a cashier for a bookstore and earn $6 per hour. You also baby sit and earn $6 per hour. You want to earn at least $60 per week, but would like to work no more than 12 hours per week. Which system of inequalities, along with y ≥ 0 and x ≥ 0, would you use to solve the real-world problem?

Answer 1

To solve the problem, you can use the system of inequalities x + y ≤ 12 and 6x + 6y ≥ 60, where x represents the number of hours worked as a cashier, and y represents the number of hours worked as a babysitter.

Step-by-step explanation:

To solve the real-world problem of earning at least $60 per week by working no more than 12 hours per week, we can use a system of inequalities. Let x represent the number of hours worked as a cashier and y represent the number of hours worked as a babysitter.

The first inequality is x + y ≤ 12, which ensures that the total number of hours worked does not exceed 12.

The second inequality is 6x + 6y ≥ 60, which ensures that the total earnings from both jobs is at least $60.

Therefore, the system of inequalities is:

• x + y ≤ 12
• 6x + 6y ≥ 60
• y ≥ 0
• x ≥ 0

Answer 2

For this case we first define varials:
x: number of hours working as cashier
y: number of hours working as a baby sit
We now write the system of equations:
6x + 6y ≥ 60
x + y ≤ 12
Answer:
to solve the real-world problem the system of inequalities is:
6x + 6y ≥ 60
x + y ≤ 12