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2/3 (a-b) =c, solve for a
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2/3 (a-b) =c, solve for a

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(2)/(3)(a-b)=c\ \ \ \ |\cdot3\\\\2(a-b)=3c\\\\2a-2b=3c\ \ \ \ |+2b\\\\2a=3c+2b\ \ \ \ |:2\\\\\boxed{a=(3c+2b)/(2)}
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