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The fish population in a certain part of the ocean (in thousands of fish) as a function of the water's temperature (in degrees celsius) is modeled by: p(x)=-2(x-9)^2+200, what is the maximum number of fish?

User Sfs
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2 Answers

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The maximum number of fish is going to be p(9) = 200
User Arian Kulp
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3 votes

Answer:

Explanation:

Given that the fish population in a certain part of the ocean (in thousands of fish) as a function of the water's temperature (in degrees celsius) is modeled by:
p(x)=-2(x-9)^2+200.

To find maximum number of fish, we use derivative test


p(x)=-2(x-9)^2+200\\p'(x) =4(x-9)\\p

Since second derivative is positive,

there will not be any maximum but only minimum


2(x-9) =0x=9

Minimum when x=9 and minimum population

p(x) =200

Maximum when x -infinity

User ShedSports
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