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Hello can you please help me posted picture of question-example-1

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This is a problem of permutation. In mathematics, the permutation relates to the fact of arranging all the member of a set into order. So, the k permutations of n are the different ordered arrangements of a k element subset of a n set. In the problem above k = 9 are the elements which are all the numerals available. On the other hand, n set is equal to 4. So, the formula of such k-permutations of n is given by:


P = (n!)/((n-k)!)

Solving for k = 9 and n = 4:


P = (9!)/((9-4)!) = 3024
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