Question

the standard molar heat of vaporization for water is 40.79 kJ/mol. How much energy would be required to vaporize 5.00 mol H2O

Answer 1

Answer:
203.95 kJ

Solution:
Heat of vaporization is the amount of energy which is required to convert a substance from liquid state to gas state. In given problem it is given that for 1 mole of water (18 g) 40.79 kJ heat is required to convert it into steam, and for 5 moles of H₂O (90 g) the amount of heat required is calculated as,

As

1 mole of water requires 40.79 kJ heat,

So,

5 mole of water will require,

= (5 mol × 40.79 kJ) ÷ 1 mol

= 203.95 kJ