Question

Currently requiring a little help on this, would not mind any answer <3

Answer 1

`\bf \sqrt{\cfrac{50x^6y^3}{9x^8}}=\cfrac{5y^c√(2y)}{dx}\\\\ -------------------------------\\\\ \sqrt{\cfrac{50x^6y^3}{9x^8}}~~ \begin{cases} 50=2\cdot 25\\ \qquad 2\cdot 5^2\\ x^6=x^(3\cdot 2)\\ \qquad (x^3)^2\\ y^3=y^(2+1)\\ \qquad y^2\cdot y\\ 9=3^2\\ x^8=x^(4\cdot 2)\\ \qquad (x^4)^2 \end{cases}\implies \cfrac{√(50x^6y^3)}{√(9x^8)}\implies \cfrac{√(2\cdot 5^2(x^3)^2\cdot y^2\cdot y)}{√(3^2(x^4)^2)}`


`\bf \cfrac{5x^3y√(2y)}{3x^4}\implies \cfrac{5y√(2y)}{3x^4x^(-3)}\implies \cfrac{5y√(2y)}{3x^(4-3)}\implies \cfrac{5y^{\stackrel{\downarrow }{1}}√(2y)}{\stackrel{\downarrow }{3} x}`