Question

A 7.03 nC charge is located 1.75 m from a 4.26 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.

Answer 1

Given that,

Charge, q₁ = 7.03 nC

Charge, q₂ = 4.26 nC

Distance, r = 1.75 m

To find,

The magnitude of the electrostatic force that one charge exerts on the other.

Solution,

The force between two charges at a distance is given by the formula as formula :

`F=(kq_1q_2)/(r^2)\\\\F=(9* 10^9* 7.03* 10^(-9)* 4.26* 10^(-9))/((1.75)^2)\\\\=8.8* 10^(-8)\ N`

So, the required force is
`8.8* 10^(-8)\ N`.