Question

a city us growing at the rate of 0.9% annually. if there were 3619000 residents in yhe city in 1994, find how many to the nearest ten thousand are living in that city in 2000. use y=3619000(2.7)^0.009t

Answer 1

For this case we have the following equation:
y = 3619000 (2.7) ^ 0.009t
We must evaluate the equation for the year 2000.
Therefore, we must replace the following value of t:
t = 2000 - 1994
t = 6
Substituting we have:
y = 3619000 (2.7) ^ (0.009 * 6)
y = 3818407.078
Round to the nearest ten thousand:
y = 3820000
Answer:
3820000 residents are living in that city in 2000