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5 votes
Express


2x {}^(2) - 20x + 53
In the form

2(x - p) {}^(2) + q
Where p and q are integers.

The answer to this is

2(x - 5) {}^(2) + 3
Use this result to explain why the equation

2x {}^(2) - 20x + 53 = 0
has no real roots

User Tzunghaor
by
8.3k points

1 Answer

7 votes

ax^2+bx+c=a(x-p)^2+q\ where\\\\p=(-b)/(2a);\ q=f(p)=(-(b^2-4ac))/(4a)
We have:

2x^2-20x+53\to a=2;\ b=-20;\ c=53
substitute

p=(-(-20))/(2\cdot2)=(20)/(4)=5\\\\q=f(5)=2\cdot5^2-20\cdot5+53=2\cdot25-100+53=50-100+53=3
therefore we have the answer:

2x^2-20x+53=2(x-5)^2+3

User Lyrikal
by
7.9k points

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