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5 votes
Let a=x^2+4. rewrite the following equation I terms of a and set it to equal zero.

(x^2+4)^2+32=12x^2+48

In resulting equation what is the coefficient of the a term?___

In the resulting equation, what is the constant? ____

User Anton Xue
by
8.0k points

2 Answers

6 votes

Answer:

1) -12

2) 32

Explanation:

User Sergei Zinovyev
by
9.3k points
6 votes

(x^2+4)^2+32=12x^2+48\\\\(x^2+4)^2+32=12(x^2+4)\\\\a^2+32=12a\\\\\boxed{a^2-12a+32=0}

so:

In resulting equation what is the coefficient of the a term? -12

In the resulting equation, what is the constant? 32

User Jfornoff
by
7.3k points

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