Let the station 1 as S1 and station 2 as S2. (please refer the diagram)
Distance between S1 and S2 = 25 miles
∠S2S1P = 73° and ∠S1S2P = 46°
So ∠S1PS2 = 180 - (73 +46) = 61°
According to the diagram, to find S2P we will use a sine law
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pqaifkle28h09o96gqwc9lxm7gkgpmrqti.png)
Cross multiply
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mpvnxqylty54wachjjwkqj0p4pkzsc8cbh.png)
Divide both side by 0.8746
![image](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xiq0upe4slq3g767y50td8g8fltk789s0d.png)
So distance between the plane and station 2 is 27.33 miles