15.3k views
3 votes
Please help me with this problem Please

Please help me with this problem Please-example-1

1 Answer

2 votes
It may be convenient to get the constant "out of the way" by adding its opposite. Then the square can be completed for both x- and y-terms. The square is completed by adding the squares of half the coefficients of the linear terms.

x^(2)+y^(2)-10x-14y=26\\\\(x^(2)-10x+5^(2))+(y^(2)-14y+7^(2))=26+5^(2)+7^(2)\\\\(x-5)^(2)+(y-7)^(2)=100\\\\(x-5)^(2)+(y-7)^(2)=10^(2)

We know the circle with center (h, k) and radius r will have the equation

(x-h)^(2)+(y-k)^(2)=r^(2)

By comparing the equation we have with the standard form equation for a circle, the center of the circle and its radius can now be read from the equation.
Center: (5, 7)
Radius: 10
Please help me with this problem Please-example-1
User Tonejac
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories