If

, then the characteristic polynomial of

is

which means

has eigenvalues

.
We know that if

is an eigenvalue of

, then

is an eigenvalues of

.
So if

is the only eigenvalue of

, we know that
![\pm\sqrt[4]\lambda=\pm1](https://img.qammunity.org/2019/formulas/mathematics/high-school/cmzo95f39olqdfq9ol74w3gbwjf52dn84m.png)
are the only possible eigenvalues of

. We can construct five possible characteristic polynomials for

in that case.




