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A 4x4 matrix a with real entries and a4 = i, what are the possible characteristic polynomials of a

User LuiCami
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1 Answer

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If
\mathbf A^4=\mathbf I, then the characteristic polynomial of
\mathbf A^4 is


p_(\mathbf A^4)(\lambda)=\det(\lambda\mathbf I-\mathbf A^4)=\det((\lambda-1)\mathbf I)=(\lambda-1)^4

which means
\mathbf A^4 has eigenvalues
\lambda=1.


We know that if
\chi is an eigenvalue of
\mathbf X, then
\chi^n is an eigenvalues of
\mathbf X^n.


So if
\lambda=1 is the only eigenvalue of
\mathbf A^4, we know that
\pm\sqrt[4]\lambda=\pm1 are the only possible eigenvalues of
\mathbf A. We can construct five possible characteristic polynomials for
\mathbf A in that case.


p_(\mathbf A)(\lambda)=(\lambda-1)^4

p_(\mathbf A)(\lambda)=(\lambda+1)(\lambda-1)^3

p_(\mathbf A)(\lambda)=(\lambda+1)^2(\lambda-1)^2

p_(\mathbf A)(\lambda)=(\lambda+1)^3(\lambda-1)

p_(\mathbf A)(\lambda)=(\lambda+1)^4
User Kal Zekdor
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