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What is the empirical formula of a compound that is 3.05% carbon, 0.26% hydrogen, and 96.69% iodine? question 4 options: chi3 ch2i5 c2hi7 c3h2i11?
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Apr 17, 2019
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What is the empirical formula of a compound that is 3.05% carbon, 0.26% hydrogen, and 96.69% iodine? question 4 options: chi3 ch2i5 c2hi7 c3h2i11?
Chemistry
high-school
Enverpex
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Answer: CHI3
Hope this helps!
Wteuber
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Apr 18, 2019
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empirical formula is the simplest ratio of whole numbers of components in a compound
calculating for 100 g of the compound
C H I
mass 3.05 g 0.26 g 96.69 g
number of moles 3.05 g / 12 g/mol 0.26 g / 1 g/mol 96.69 g / 127 g/mol
= 0.254 mol = 0.26 mol = 0.7613 mol
divide by the least number of moles
0.254/ 0.254 = 1.0 0.26 / 0.254 = 1.0 0.7613 / 0.254 = 2.99
when rounded off
C - 1
H - 1
I - 3
empirical formula is CHI₃
answer 1) CHI₃
David Steinhauer
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Apr 22, 2019
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David Steinhauer
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